Sin(a+b) Proof Using De Moivre's Theorem - Sine Sum of Angles

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sin(x+y) Proof - kevinrosseel
sin(x+y) Proof - kevinrosseel
This article uses De Moivres Theorem to prove the formula for sin(a+b) and cos(a+b). There are trigonometric proofs for sin(a+b) but this method is shorter.

The article "Trigonometry Sin(a+b) Cos(a+b) Sin(a)+Sin(b) Cos(a)+Cos(b)" shows how to derive several trigonometric identities, but it assumes that the formula for sin(x+y) is already known. Several websites describe the proof of the formula for sin(x+y) using trigonometry, but this article uses a simpler method based on De Moivre's Theorem. It is assumed that the student is familiar with the basic rules of logarithms and exponents.

Sin(x+y) Proof - Background

There are many instances where there is a need to know, or prove, the formula for sin(x+y). This is true for the later years of High School mathematics, as well as college math. The formula is a precursor to several other trigonometric proofs. The following identities are assumed, although they are proven elsewhere:

De Moivre's Theorem: (cosx + i.sinx)^n = cos(nx) + i.sin(nx)

where i = √(-1) by convention. (In some literature "j" is used instead of "i", so as not to confuse it with the symbol for electrical current.)

This is proven in the article "De Moivres Theorem Description With Examples and Application"

Euler's Formula: e^(ix) = cosx + i.sinx,

where e = base of natural logarithms, 2.71828...

Law of Exponents: a^(x+y) = a^x × a^y,

which is proven in the article "Basic Logarithms And Exponents Explanation And Lesson Plan"

Sin(x+y) Proof

It is known from Euler's formula that

e^(i.x) = cos(x) + i.sin(x)

Letting x = a + b,

e^(i.x) = e^(i.(a+b))

= e^(i.a + i.b)

= e^(i.a) × e^(i.b), from the Law of Exponents

But e^(i.(a+b)) = cos(a+b) + i.sin(a+b) from Euler's formula, so

e^(i.a) × e^(i.b) = cos(a+b) + i.sin(a+b)

Expanding the left-hand side,

[cos(a) + i.sin(a)] × [cos(b) + i.sin(b)] = cos(a+b) + i.sin(a+b), so

cos(a).cos(b) + i².sin(a).sin(b) + i.sin(a).cos(b) + i. cos(a).sin(b) = cos(a+b) + i.sin(a+b), so

cos(a).cos(b) - sin(a).sin(b) + i.(sin(a).cos(b) + cos(a).sin(b)) = cos(a+b) + i.sin(a+b)

Equating real and imaginary parts,

cos(a).cos(b) - sin(a).sin(b) = cos(a+b), and

sin(a).cos(b) + cos(a).sin(b) = sin(a+b)

Q.E.D.

So the proofs for the sum of sines and cosines of angles have been shown very simply.

Summary of Sin(x+y) and Cos(x+y) Uses

Many other trigonometric proofs depend on the formula for sin(x+y) and cos(x+y). The result is widely used throughout math courses at many levels, and the result is used throughout engineering, including electronics and construction. The proof shown here is shorter and more easily understood than the more widely-known proof that uses two right-angled triangles.

References For Proof of Sin(a+b) and Cos(a+b)

The proofs shown here depend only on the Law of Exponents, Euler's formula, and De Moivre's Theorem, and no other references have been used. (De Moivre's Theorem is not really a fundamental proof either, since it is derived from Euler's formula). One additional exercise that is useful for the student is to try to prove the formula for Sin(a+b+c): this should be tried using the trigonometric method, and then using the method used here based on Euler's formula. That way, the real power of Euler's formula will be seen.

Me at Lake Garda, Summer 2008, Photograph taken by Alison Bell

Martin Bell - Martin holds a B.Sc. degree in chemical engineering, and an M.Sc. degree in electronics and computing. He has spent more than 25 years ...

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Comments

Apr 27, 2011 1:05 AM
Guest :
can you provide examples?
Sep 24, 2011 7:48 PM
Guest :
Hello

I have a question regarding this proof:
I was taught the proof of Euler's formula but this one relied on the property sin(a+b) = sina*cosb + sinb*cosa

Although, here, you proof sin(a+b) using it's own property to proof Euler's formula..

See what I mean? This proof doesn't really start off from scratch..

Or it would be fine if you could prove that e^ix = cosx + isinx WITHOUT using these sin formulas...

Just to summarize, you're proving something using a formula (Euler's formula) when the latter requires that sin(a+b) = sina*cosb + sinb*cosa

Would I be right?
Thank you
Sep 25, 2011 2:54 AM
Martin Bell :
Guest,

the proof of Eulers formula does not require prior proof of sin(a+b).

Euler's original proof for his formula was based on the power series for e^x, and sin(x)

i.e.

e^x = 1+x+x²/2!+x³/3!+....

sin(x)=x-x³/3!+x^5/5!

Hope this helps,
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